Author: Panagiotis
22
Aug
In
[1, p. 35 exercise 2.18] we are asked to prove that the inverse of a complex matrix

may be found by first inverting
to yield
and then letting

.
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Author: Panagiotis
16
Aug
In
[1, p. 35 exercise 2.17] we are asked to verify the alternative expression
[1, p. 33 (2.77)] for a hermitian function.
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Author: Panagiotis
12
Aug
In
[1, p. 35 exercise 2.16] we are asked to verify the formulas given for the complex gradient of a hermitian and a linear form
[1, p. 31 (2.70)]. To do so, we are instructed to decompose the matrices and vectors into their real and imaginary parts as
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Author: Panagiotis
25
Jun
In
[1, p. 35 exercise 2.15] we are asked to verify the formulas given for the gradient of a quadratic and linear form
[1, p. 31 (2.61)].
The corresponding formulas are
and
where

is a symmetric

matrix with elements

and

is a real

vector with elements

and

denotes the gradient of a real function in respect to

.
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Author: Panagiotis
28
Mai
In
[1, p. 35 exercise 2.14] we are asked to consider the solution to the set of linear equations
where

is a

hermitian matrix given by:
and

is a complex

vector given by
The complex vectors are defined in
[1, p.22, (2.27)]. Furthermore we are asked to assumed that

,

for

are distinct integers in the range
![[-n/2,n/2-1]](https://lysario.de/wp-content/cache/tex_24916734a0a5230271c84429761581eb.png)
for

even and
![[-(n-1)/2,(n-1)/2]](https://lysario.de/wp-content/cache/tex_b9ee4eee41d27a8e5eea256f738e00e2.png)
for

odd.

is defined to be a

vector.
It is requested to show that

is a singular matrix (assuming

) and that there are infinite number of solutions.
A further task is to find the general solution and also the minimum norm solution of the set of linear equations. The
hint provided by the exercise is to note that

are eigenvectors of

with nonzero eigenvalues and then to assume a solution of the form
where

for

and solve for

.
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