"ούτω γάρ ειδέναι το σύνθετον υπολαμβάνομεν, όταν ειδώμεν εκ τίνων και πόσων εστίν …"
22 Dez
 hermitian matrix
 hermitian matrix  given by [1, (2.27)] by recursively applying Woodbury’s identity. This should be done by considering the cases where
 given by [1, (2.27)] by recursively applying Woodbury’s identity. This should be done by considering the cases where  are arbitrary and where
 are arbitrary and where  ,
,   for
 for  beeing distinct integers in the range
 beeing distinct integers in the range ![\left[ -n/2,n/2-1 \right]](https://lysario.de/wp-content/cache/tex_349760367e158b72823c089231e45245.png) for
 for  even and
 even and ![\left[ -(n-1)/2,(n-1)/2 \right]](https://lysario.de/wp-content/cache/tex_bbbbf77ffaa65be463cde297b83e452b.png) for
 for  odd.  
 read the conclusion >
 odd.  
 read the conclusion >