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	<title>Kommentare zu: Steven M. Kay: “Modern Spectral Estimation – Theory and Applications”,p. 35 exercise 2.15</title>
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	<link>https://lysario.de/solved_problems/steven-m-kay-%e2%80%9cmodern-spectral-estimation-%e2%80%93-theory-and-applications%e2%80%9dp-35-exercise-2-15</link>
	<description>&#34;ούτω γάρ ειδέναι το σύνθετον υπολαμβάνομεν, όταν ειδώμεν εκ τίνων και πόσων εστίν ...&#34;</description>
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		<title>Von: Steven M. Kay: “Modern Spectral Estimation – Theory and Applications”,p. 35 exercise 2.16</title>
		<link>https://lysario.de/solved_problems/steven-m-kay-%e2%80%9cmodern-spectral-estimation-%e2%80%93-theory-and-applications%e2%80%9dp-35-exercise-2-15/comment-page-1#comment-263</link>
		<dc:creator>Steven M. Kay: “Modern Spectral Estimation – Theory and Applications”,p. 35 exercise 2.16</dc:creator>
		<pubDate>Wed, 11 Aug 2010 22:13:15 +0000</pubDate>
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		<description><![CDATA[[...] of the gradient of a quadratic form of a real matrix which is not symmetric. We reproduce from [2, relation (4) from the solution of exercise 2.15] the formula for the real matrix  and the real vector [...]]]></description>
		<content:encoded><![CDATA[<p>[...] of the gradient of a quadratic form of a real matrix which is not symmetric. We reproduce from [2, relation (4) from the solution of exercise 2.15] the formula for the real matrix  and the real vector [...]</p>
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